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LeetCode 946. 验证栈序列(Validate Stack Sequences) 26

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946. 验证栈序列
946. Validate Stack Sequences

题目描述
Given two sequences pushed and popped with distinct values, return true if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack.

每日一算法2019/5/29Day 26LeetCode946. Validate Stack Sequences

Example 1:

Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
Output: true
Explanation: We might do the following sequence:
push(1), push(2), push(3), push(4), pop() -> 4,
push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1

Example 2:

Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]
Output: false
Explanation: 1 cannot be popped before 2.

Note:

  1. 0 <= pushed.length == popped.length <= 1000
  2. 0 <= pushed[i], popped[i] < 1000
  3. pushed is a permutation of popped.
  4. pushed and popped have distinct values.

Java 实现

import java.util.Stack;

class Solution {
    public boolean validateStackSequences(int[] pushed, int[] popped) {
        int n = pushed.length;
        Stack<Integer> stack = new Stack<>();
        for (int pushIndex = 0, popIndex = 0; pushIndex < n; pushIndex++) {
            stack.push(pushed[pushIndex]);
            while (popIndex < n && !stack.isEmpty() && stack.peek() == popped[popIndex]) {
                stack.pop();
                popIndex++;
            }
        }
        return stack.isEmpty();
    }
}

参考资料

LeetCode 946. 验证栈序列(Validate Stack Sequences) 26

原文:https://www.cnblogs.com/hglibin/p/10946672.html

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