鸡兔同笼-数学解法

public void chr() {
    for (int i = 0; i <= 35; i++) {
        if (i * 2 + (35 - i) * 4 == 94) {
            System.out.println("笼子里有雉[" + i + "]兔[" + (35 - i) + "]");
        }
    }
}

public void chr1() {
    int head = 35;
    int foot = 94;
    int x, y;
    y = foot / 2 - head;
    x = 35 - y;
    System.out.println("笼子里有雉[" + x + "]兔[" + y + "]");
}