下面程序的输出是：
3+4i
5+6i
请补足Complex类的成员函数。不能加成员变量。
#include <iostream>
#include <cstring>
#include <cstdlib>
using namespace std;
class Complex {
private:
double r,i;
public:
void Print() {
cout << r << "+" << i << "i" << endl;
}
// 在此处补充你的代码
};
int main() {
Complex a;
a = "3+4i"; a.Print();
a = "5+6i"; a.Print();
return 0;
}
无
3+4i 5+6i
#include <iostream> #include <cstring> #include <cstdlib> using namespace std; class Complex { private: double r, i; public: void Print() { cout << r << "+" << i << "i" << endl; } // 在此处补充你的代码 #if 0 void operator=(string s) { //由原型知，若省略第2个参数，则默认从位置0（即第1个字符）起开始查找 int position = s.find("+",0); string firstPart = s.substr(0, position); string secondPart = s.substr(position + 1, s.length() - position - 2); r = atof(firstPart.c_str()); i = atof(secondPart.c_str()); } #endif Complex& operator=(string s) { //由原型知，若省略第2个参数，则默认从位置0（即第1个字符）起开始查找 int position = s.find("+", 0); string firstPart = s.substr(0, position); string secondPart = s.substr(position + 1, s.length() - position - 2); r = atof(firstPart.c_str()); i = atof(secondPart.c_str()); return *this; } }; int main() { Complex a; a = "30+40i"; a.Print(); a = "500+6i"; a.Print(); while (1); return 0; }
下面的MyInt类只有一个成员变量。MyInt类内部的部分代码被隐藏了。假设下面的程序能编译通过，且输出结果是:
4,1
请写出被隐藏的部分。（您写的内容必须是能全部放进 MyInt类内部的，MyInt的成员函数里不允许使用静态变量）。
#include <iostream>
using namespace std;
class MyInt {
int nVal;
public:
MyInt(int n) { nVal = n; }
int ReturnVal() { return nVal; }
// 在此处补充你的代码
};
int main () {
MyInt objInt(10);
objInt-2-1-3;
cout << objInt.ReturnVal();
cout <<",";
objInt-2-1;
cout << objInt.ReturnVal();
return 0;
#include <iostream> using namespace std; class MyInt { int nVal; public: MyInt(int n) { nVal = n; } int ReturnVal() { return nVal; } // 在此处补充你的代码 MyInt& operator-(int w) { nVal -= w; return *this; } }; int main() { MyInt objInt(10); objInt - 2 - 1 - 3; cout << objInt.ReturnVal(); cout << ","; objInt - 2 - 1; cout << objInt.ReturnVal(); while (1); return 0; }
注意： 总时间限制: 1000ms 内存限制: 65536kB
写一个二维数组类 Array2,使得下面程序的输出结果是：
0,1,2,3,
4,5,6,7,
8,9,10,11,
next
0,1,2,3,
4,5,6,7,
8,9,10,11,
程序：
#include <iostream>
#include <cstring>
using namespace std;
// 在此处补充你的代码
int main() {
Array2 a(3,4);
int i,j;
for( i = 0;i < 3; ++i )
for( j = 0; j < 4; j ++ )
a[i][j] = i * 4 + j;
for( i = 0;i < 3; ++i ) {
for( j = 0; j < 4; j ++ ) {
cout << a(i,j) << ",";
}
cout << endl;
}
cout << "next" << endl;
Array2 b; b = a;
for( i = 0;i < 3; ++i ) {
for( j = 0; j < 4; j ++ ) {
cout << b[i][j] << ",";
}
cout << endl;
}
return 0;
}
无
0,1,2,3,
4,5,6,7,
8,9,10,11,
next
0,1,2,3,
4,5,6,7,
8,9,10,11,
无
0,1,2,3, 4,5,6,7, 8,9,10,11, next 0,1,2,3, 4,5,6,7, 8,9,10,11,
#include <iostream> #include <cstring> using namespace std; // 在此处补充你的代码 class Array2 { private: int i; int j; int * a; public: //constructor function Array2() { a = NULL; } Array2(int i_, int j_) { i = i_; j = j_; a = new int[i*j]; } // copy constructor ? is needed??? Array2(Array2 &t) { i = t.i; j = t.j; a = new int[i*j]; memcpy(a, t.a, sizeof(int)*i*j); } // overload [] and = and ( ) Array2 & operator=(const Array2 &t) { if (a != NULL) delete[] a; i = t.i; j = t.j; a = new int[i*j]; memcpy(a, t.a, sizeof(int)*i*j); return *this; } ~Array2() { if (a != NULL) delete[] a; } // 将返回值设为int的指针，则可以应用第二个【】，不用重载第二个【】操作符 int *operator[] (int i_) { return a + i_*j; // 觉得有问题 } int &operator() (int i_, int j_) { return a[i_*j + j_]; } }; int main() { Array2 a(3, 4); int i, j; for (i = 0; i < 3; ++i) for (j = 0; j < 4; j++) a[i][j] = i * 4 + j; for (i = 0; i < 3; ++i) { for (j = 0; j < 4; j++) { cout << a(i, j) << ","; } cout << endl; } cout << "next" << endl; Array2 b; b = a; for (i = 0; i < 3; ++i) { for (j = 0; j < 4; j++) { cout << b[i][j] << ","; } cout << endl; } while (1); return 0; }
《C++程序设计POJ》《WEEK4 运算符重载 》《第四周-编程填空》
原文：https://www.cnblogs.com/focus-z/p/11029252.html