Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.
Each input file contains one test case. Each case occupies one line which contains an N (≤).
For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.
12345
one five
思路：求和，英文输出，但是需要注意特殊情况：零的时候。
1 #include <iostream> 2 #include <algorithm> 3 #include <string> 4 #include <cstring> 5 #include <cstdio> 6 #include <stack> 7 using namespace std; 8 string s; 9 void _print(int x) 10 { 11 stack<int> s; 12 while(x){ 13 s.push(x%10); 14 x/=10; 15 } 16 while(!s.empty()){ 17 switch(s.top()){ 18 case 0: cout<<"zero"; break; 19 case 1: cout<<"one";break; 20 case 2: cout<<"two";break; 21 case 3: cout<<"three";break; 22 case 4: cout<<"four";break; 23 case 5: cout<<"five";break; 24 case 6: cout<<"six";break; 25 case 7: cout<<"seven";break; 26 case 8: cout<<"eight";break; 27 case 9: cout<<"nine";break; 28 } 29 s.pop(); 30 if(!s.empty()) cout<<" "; 31 } 32 cout<<endl; 33 } 34 int main() 35 { 36 while(cin>>s){ 37 int sum=0; 38 for(int i=0;i<s.length();i++){ 39 sum+=int(s[i]-‘0‘); 40 } 41 if(sum==0) cout<<"zero"<<endl; 42 else _print(sum); 43 } 44 return 0; 45 }
PAT (Advanced Level) Practice 1005 Spell It Right (20 分) （switch）
原文：https://www.cnblogs.com/shixinzei/p/11053264.html