首页 > 编程语言 > 详细

java8新特性Lambda(4)

时间:2019-06-26 13:44:15      阅读:86      评论:0      收藏:0      [点我收藏+]
import java.util.ArrayList;
import java.util.List;

import com.test.lambda.Person.Sex;

public class Lambda03 {

    public static void main(String[] args) {
        List<Person> list = new ArrayList<Person>();
        Person p1 = new Person("zhangsan",Sex.MALE,1);
        Person p2 = new Person("lisi",Sex.MALE,1);
        Person p3 = new Person("lisi",Sex.MALE,2);
        Person p4 = new Person("xiaolan",Sex.FEMALE,3);
        Person p5 = new Person("xiaolan",Sex.FEMALE,3);
        Person p6 = new Person("xiaolan",Sex.FEMALE,3);
        list.add(p1);
        list.add(p2);
        list.add(p3);
        list.add(p4);
        list.add(p5);
        list.add(p6);
        list.removeIf(n->Sex.MALE.equals(n.getSex())&&2==n.getAge());//移除男性并且年龄2的数据
        System.out.println(list);
        
    }
}

java8新特性Lambda(4)

原文:https://www.cnblogs.com/zzlcome/p/11089217.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!