- ????JDK :OpenJDK-11
- ?????OS :CentOS 7.6.1810
- ?????IDE :Eclipse 2019?03
- typesetting :Markdown
?
package per.jizuiku.base;
import java.util.Scanner;
/**
* @author 给最苦
* @date 2019/06/29
* @blog www.cnblogs.com/jizuiku
*/
class Demo {
/**
* @param args
*/
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String myStr = sc.nextLine();
System.out.println("resut:" + myStr);
sc.close();
}
}
?
hello world
resut:hello world
?
/**
* Advances this scanner past the current line and returns the input
* that was skipped.
*
* This method returns the rest of the current line, excluding any line
* separator at the end. The position is set to the beginning of the next
* line.
*
* <p>Since this method continues to search through the input looking
* for a line separator, it may buffer all of the input searching for
* the line to skip if no line separators are present.
*
* @return the line that was skipped
* @throws NoSuchElementException if no line was found
* @throws IllegalStateException if this scanner is closed
*/
public String nextLine() {
modCount++;
if (hasNextPattern == linePattern())
return getCachedResult();
clearCaches();
String result = findWithinHorizon(linePattern, 0);
if (result == null)
throw new NoSuchElementException("No line found");
MatchResult mr = this.match();
String lineSep = mr.group(1);
if (lineSep != null)
result = result.substring(0, result.length() - lineSep.length());
if (result == null)
throw new NoSuchElementException();
else
return result;
}
?
?
感谢帮助过 给最苦 的人们。
Java、Groovy和Scala等基于JVM的语言,优秀,值得学习。
规范的命名和代码格式等,有助于沟通和理解。
JVM的配置、监控与优化,比较实用,值得学习。
Java基础 Scanner 使用nextLine接收字符串
原文:https://www.cnblogs.com/jizuiku/p/11107752.html