Largest Number At Least Twice of Others

In a given integer array nums, there is always exactly one largest element.

Find whether the largest element in the array is at least twice as much as every other number in the array.

If it is, return the index of the largest element, otherwise return -1.

Example 1:

Input: nums = [3, 6, 1, 0]
Output: 1
Explanation: 6 is the largest integer, and for every other number in the array x,
6 is more than twice as big as x.  The index of value 6 is 1, so we return 1.

Example 2:

Input: nums = [1, 2, 3, 4]
Output: -1
Explanation: 4 isn‘t at least as big as twice the value of 3, so we return -1.

分析：这题就是让你找出第一大和第二大的数。

 1 class Solution {
 2     public int dominantIndex(int[] nums) {
 3         int max = -1, index = -1, second = -1;
 4         for (int i = 0; i < nums.length; i++) {
 5             if (nums[i] > max) {
 6                 second = max;
 7                 max = nums[i];
 8                 index = i;
 9             } else if (nums[i] > second)
10                 second = nums[i];
11         }
12         return second * 2 <= max ? index : -1;
13     }
14 }

Largest Number At Least Twice of Others

原文：https://www.cnblogs.com/beiyeqingteng/p/11149054.html