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LeetCode-268. Missing Number

时间:2019-07-17 22:21:52      阅读:128      评论:0      收藏:0      [点我收藏+]

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

Example 1:

Input: [3,0,1]
Output: 2

Example 2:

Input: [9,6,4,2,3,5,7,0,1]
Output: 8

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

    public int missingNumber(int[] nums) {
        int re = 0;
        for(int i =0;i<nums.length;i++){
            re = re^i^nums[i];//x^a^a =x;x^0=x
        }
        re = re^nums.length;
        return re;
    }

 

LeetCode-268. Missing Number

原文:https://www.cnblogs.com/zhacai/p/11203952.html

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