首页 > 其他 > 详细

LeetCode开心刷题二十四天——45. Jump Game II

时间:2019-07-25 20:10:10      阅读:120      评论:0      收藏:0      [点我收藏+]
45. Jump Game II
Hard

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Your goal is to reach the last index in the minimum number of jumps.

Example:

Input: [2,3,1,1,4]
Output: 2
Explanation: The minimum number of jumps to reach the last index is 2.
    Jump 1 step from index 0 to 1, then 3 steps to the last index.

Note:

You can assume that you can always reach the last index.

Main Idea:

when write the code except for the main idea,please pay attention to >= > the difference may cause result different

#include<stdio.h>
#include<iostream>
#include<string>
#include<vector>
using namespace std;
class Solution
{
public:
    int jump(vector<int>& nums)
    {
        int res=0,r=0,l=0,next_r=0;
        int times=nums.size()-1;
        while(r<times)
        {
            for(int i=l;i<=r;i++)
            {
                next_r=max(next_r,nums[i]+i);
            }
            l=r+1;
            r=next_r;
            res++;
        }
        return res;
    }

};
int main()
{
    Solution s;
    vector<int> v;
    v.push_back(2);
    v.push_back(3);
    v.push_back(1);
    v.push_back(1);
    v.push_back(4);
    int res=s.jump(v);
    cout<<res<<endl;
    return 0;
}

 

LeetCode开心刷题二十四天——45. Jump Game II

原文:https://www.cnblogs.com/Marigolci/p/11246365.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!