nums = [1,3,12,23,42,31,1123]
nums.sort() #对列表从小到大排序
nums.sort(reverse = True) #对列表从大到小排序
nums.reverse() #倒序，逆序
infors = [{"name":"laowang","age":10},{"name":"xiaoming","age":20},{"name":"banzhang","age":15}]
infors.sort(key=lambda x:x[‘name‘])
print(infors)
原文：https://www.cnblogs.com/ql0302/p/11267054.html