Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
O(n^2)解法超时
public class Solution { public int maxArea(int[] height) { int area=0,newarea=0; int n=height.length; for(int i=0;i<n-1;i++){ for(int j=i+1;j<n;j++){ int minHeight=Math.min(height[i],height[j]); int width=height[j]-height[i]; newarea=minHeight*width; if(area<newarea){ area=newarea; } } } return area; } }
public class Solution { public int maxArea(int[] height) { int result=0; int n=height.length; int low=0,high=n-1; while(low<high){ int area=Math.min(height[high],height[low])*(high-low); if(result<area) result=area; if(height[high]>height[low]) low++; else high--; } return result; } }
Container With Most Water,布布扣,bubuko.com
原文:http://blog.csdn.net/dutsoft/article/details/38580413