自然常数e的算法

1 def fun_e (n):
2     sum = 0
3     
4     sum += (1+1/n)**n
5             
6     return sum
7 print(fun_e(620000000))
8     
  #结果：2.7182816890306443

1 def fun_e (n):
2     sum = 1
3     s = 1
4     for i in range(1,n+1):
5         for j in range(1,i+1):
6             s = s*j
7         sum += 1/s
8     return sum
9 print(fun_e(1000))

 #结果：2.5868345309364718