由于js都是以浮点存储的小数,小数运算时,可能会失去精度。下面专门写一些方法,来避免问题。
//js 加法计算 //调用:accAdd(arg1,arg2) //返回值:arg1加arg2的精确结果 function accAdd(arg1, arg2) { var r1, r2, m; try { r1 = arg1.toString().split(".")[1].length } catch (e) { r1 = 0 } try { r2 = arg2.toString().split(".")[1].length } catch (e) { r2 = 0 } m = Math.pow(10, Math.max(r1, r2)) return ((arg1 * m + arg2 * m) / m).toFixed(2); } accAdd(0.2, 0.4) //js 减法计算 //调用:Subtr(arg1,arg2) //返回值:arg1减arg2的精确结果 function Subtr(arg1, arg2) { var r1, r2, m, n; try { r1 = arg1.toString().split(".")[1].length } catch (e) { r1 = 0 } try { r2 = arg2.toString().split(".")[1].length } catch (e) { r2 = 0 } m = Math.pow(10, Math.max(r1, r2)); //last modify by deeka //动态控制精度长度 n = (r1 >= r2) ? r1 : r2; return ((arg1 * m - arg2 * m) / m).toFixed(2); } //js 乘法函数 //调用:accMul(arg1,arg2) //返回值:arg1乘以arg2的精确结果 function accMul(arg1, arg2) { var m = 0, s1 = arg1.toString(), s2 = arg2.toString(); try { m += s1.split(".")[1].length } catch (e) {} try { m += s2.split(".")[1].length } catch (e) {} return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m) } //js 除法函数 //调用:accDiv(arg1,arg2) //返回值:arg1除以arg2的精确结果 function accDiv(arg1, arg2) { var t1 = 0, t2 = 0, r1, r2; try { t1 = arg1.toString().split(".")[1].length } catch (e) {} try { t2 = arg2.toString().split(".")[1].length } catch (e) {} with(Math) { r1 = Number(arg1.toString().replace(".", "")) r2 = Number(arg2.toString().replace(".", "")) return (r1 / r2) * pow(10, t2 - t1); } }
原文:https://www.cnblogs.com/camille666/p/js_float_number.html