首先根节点以及其左右子树,左子树的左子树和右子树的右子树相同
左子树的右子树和右子树的左子树相同即可,采用递归
非递归也可,采用栈或队列存取各级子树根节点
boolean isSymmetrical(TreeNode pRoot) { boolean flag=true; if (pRoot==null||(pRoot.left==null&&pRoot.right==null)) { return true; } TreeNode leftNode=pRoot.left; TreeNode rightNode=pRoot.right; return comRoot(leftNode,rightNode); } private boolean comRoot(TreeNode leftNode, TreeNode rightNode) { if(leftNode == null) return rightNode==null; if(rightNode == null) return false; if (leftNode.val!=rightNode.val) { return false; } return comRoot(leftNode.right, rightNode.left)&&comRoot(leftNode.left, rightNode.right); }
原文:https://www.cnblogs.com/Transkai/p/11416203.html