顺序:
(从此处开始可以使用select中指定的别名)
select
sum(goods.number)
from order
left join goods on goods.order_id = order.id
where
order.status=1
group by order.user_id
having order.add_time > ‘2019-08-27 00:00:00‘
order by goods.number desc
原文:https://www.cnblogs.com/UniqueColor/p/11417553.html