业务表增长速度较快,单表数据较大,对表的读写有影响。 思路:化整为零,把单表拆解为多表,按指定规则选择表 以Laravel项目为例,分表读取代码如下: public function changeTable($companyId) { // 分表算法,根据companyId选择分表,请勿修改算法,以免混淆分表数据 $posfix = intval($companyId) % 10; $tableName = $posfix ? "demo_$posfix" : ‘demo‘; return $this->setTable($tableName); } 调用方法: public function countCompanyData($companyId, $condition) { return $this->changeTable($companyId)->multiwhere($condition)->count(); } 算法实现后,就差表数据迁移了 步骤一,先执行 SHOW CREATE TABLE `demo`; 得到原始表的创建语句,然后,加个下标,就是分表的创建语句了 步骤二,创建所需要的所有分表,需要创建 1~9 编号的分表,这里以编号1为例 CREATE TABLE `demo_1` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT COMMENT ‘主键ID‘, `company_id` int(11) unsigned NOT NULL COMMENT ‘商家ID‘, `content` varchar(255) NOT NULL COMMENT ‘短信内容‘, `phone` varchar(11) NOT NULL COMMENT ‘手机号‘ PRIMARY KEY (`id`), KEY `company_id` (`company_id`), KEY `Phone` (`phone`,`company_id`), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT=‘演示表‘; 步骤三,创建好分表后,执行迁移语句 INSERT INTO `demo_1` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 1; INSERT INTO `demo_2` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 2; INSERT INTO `demo_3` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 3; INSERT INTO `demo_4` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 4; INSERT INTO `demo_5` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 5; INSERT INTO `demo_6` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 6; INSERT INTO `demo_7` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 7; INSERT INTO `demo_8` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 8; INSERT INTO `demo_9` SELECT * FROM `demo` WHERE MOD(`company_id`, 10) = 9; 步骤四,备份原始表(demo表)的数据
步骤五,删除已迁移的数据,留下属于 编号0 表的数据 DELETE FROM `demo` WHERE MOD(`company_id`, 10) != 0; P.S:修改后所有的SQL操作,都应该含有 company_id 信息,这样才能找到具体的分表。 如果业务中有和company_id无关的汇总类的查询,已统计所有记录为例,那么可以 public function countTable($condition) { $posfixList = range(0, 9); $sum = 0; foreach ($posfixList as $posfix) { $tableName = $posfix ? "demo_$posfix" : ‘demo‘ ; $count = $this->setTable($tableName)->multiwhere($condition)->sum(‘id‘); } $sum += $count; return $sum; }
原文:https://www.cnblogs.com/funsion/p/11424703.html