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107.二叉树的遍历Ⅱ

时间:2019-08-28 22:15:02      阅读:67      评论:0      收藏:0      [点我收藏+]
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    def levelOrderBottom(self, root: TreeNode) -> List[List[int]]:
        if root is None:
            return []
        
        result, current = [], [root]
        while current:
            next_level, vals = [], []
            for node in current:
                vals.append(node.val)
                if node.left:
                    next_level.append(node.left)
                if node.right:
                    next_level.append(node.right)
            current = next_level
            result.append(vals)
        return result[::-1]

 

107.二叉树的遍历Ⅱ

原文:https://www.cnblogs.com/WJZheng/p/11426664.html

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