首页 > 其他 > 详细

110. Balanced Binary Tree

时间:2019-08-30 09:15:52      阅读:96      评论:0      收藏:0      [点我收藏+]

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Note: A leaf is a node with no children.

Example:

Given binary tree [3,9,20,null,null,15,7],

    3
   /   9  20
    /     15   7

return its depth = 3.

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public boolean isBalanced(TreeNode root) {
        if(root == null) return true;
        int l = depth(root.left);
        int r = depth(root.right);
        return Math.abs(l - r) < 2 && isBalanced(root.left) && isBalanced(root.right);
    }
    public int depth(TreeNode root){
        if(root == null) return 0;
        return Math.max(depth(root.left), depth(root.right)) + 1;
    }
}

在maxDepth of BST的基础上进一步做文章。

110. Balanced Binary Tree

原文:https://www.cnblogs.com/wentiliangkaihua/p/11432879.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!