字符串
增
删
改
查
列表
增
删
改
查
元祖
增
删
改
查
字典
dic1={"k1‘:"v1","k2":"v2"}
增
①
dic1={"k1":"v1","k2":"v2"}
dic1["k3"]="v4"
print(dic1)
②
③
④
⑤
⑥
删
①
dic1={"k1":"v1","k2":"v2"}
dic2={"k3":"v3","k4":"v4"}
del dic1[‘k1‘]
print(dic1)
②
dic1={"k1":"v1","k2":"v2"}
dic2={"k3":"v3","k4":"v4"}
dic1.pop("k1")
print(dic1)
③
clear
④
remove
改
①
dic1={"k1":"v1","k2":"v2"}
dic2={"k3":"v3","k4":"v4"}
dic3=dic1.update(dic2)
print(dic1)
②
③
④
查
①
dic1={"k1":"v1","k2":"v2"}
dic2={"k3":"v3","k4":"v4"}
values=dic1.get("k1")
print(values)
>>v1
dic1={"k1":"v1","k2":"v2"}
dic2={"k3":"v3","k4":"v4"}
values=dic1.get("k5")
print(values)
none
②
③
④
dic1 = {‘a‘:‘b‘}
dic2 = {‘c‘:‘d‘}
从dic1中获取key为d对应的value，没有不报错，有输出value
将dic2添加到dic1中
修改dic1中的a的value为m
dic3 = {‘a‘:‘b‘, ‘c‘:‘d‘}
循环获取dic3 的key value
menu = {
"北京":{"沙河":"bat","昌平":{"a":"b","c":"d"}}
}
获取menu中a对应的value
-----------------------
1.python2和3的默认编码：*
2.pass,break,continue
3.gdk ->utf-8 **
4.去除字符串的空格
5."+".join(li)
6.数据类型的增删改查
③
原文：https://www.cnblogs.com/hantongxue/p/11437077.html