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(Easy) Maximum Product of Three Numbers - LeetCode

时间:2019-09-04 16:46:42      阅读:78      评论:0      收藏:0      [点我收藏+]

Description:

Given an integer array, find three numbers whose product is maximum and output the maximum product.

Example 1:

Input: [1,2,3]
Output: 6

 

Example 2:

Input: [1,2,3,4]
Output: 24

 

Note:

  1. The length of the given array will be in range [3,104] and all elements are in the range [-1000, 1000].
  2. Multiplication of any three numbers in the input won‘t exceed the range of 32-bit signed integer.

 

Accepted
80,213
Submissions
172,564

Solution:

class Solution {
    public int maximumProduct(int[] nums) {
        
        Arrays.sort(nums);
        
        int max_1  = nums[nums.length-1]*nums[nums.length-2]*nums[nums.length-3];
        
        //int max_2 = nums[0]*nums[1]*nums[2];
        
        int max_3 = nums[0]* nums[1]* nums[nums.length-1];
        
        
        
        for(int i = 0; i<nums.length; i++){
            System.out.print(nums[i]);
        }
        
        return Get(max_1,max_3);
        
    }
    
    public static int Get(int a,  int c){
        return a>c? a: c;
    }
}

 

 

(Easy) Maximum Product of Three Numbers - LeetCode

原文:https://www.cnblogs.com/codingyangmao/p/11459412.html

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