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jackson将json数组转成List、普通数组。

时间:2019-09-05 12:27:32      阅读:506      评论:0      收藏:0      [点我收藏+]
package com.mkyong;

import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.ObjectMapper;

import java.io.IOException;
import java.util.Arrays;
import java.util.List;

public class JacksonArrayExample {

    public static void main(String[] args) {

        ObjectMapper mapper = new ObjectMapper();
        String json = "[{\"name\":\"mkyong\", \"age\":37}, {\"name\":\"fong\", \"age\":38}]";

        try {

            // 1. convert JSON array to Array objects
            Person[] pp1 = mapper.readValue(json, Person[].class);

            System.out.println("JSON array to Array objects...");
            for (Person person : pp1) {
                System.out.println(person);
            }

            // 2. convert JSON array to List of objects
            List<Person> ppl2 = Arrays.asList(mapper.readValue(json, Person[].class));

            System.out.println("\nJSON array to List of objects");
            ppl2.stream().forEach(x -> System.out.println(x));

            // 3. alternative
            List<Person> pp3 = mapper.readValue(json, new TypeReference<List<Person>>() {});

            System.out.println("\nAlternative...");
            pp3.stream().forEach(x -> System.out.println(x));

        } catch (IOException e) {
            e.printStackTrace();
        }

    }
}
import lombok.Data;
import lombok.ToString;

@Data
@ToString
public class Person {
    private String name;
    private Integer age;
}

maven依赖

 

<dependency>
        <groupId>com.fasterxml.jackson.core</groupId>
        <artifactId>jackson-databind</artifactId>
        <version>2.9.8</version>
    </dependency>

 

 

 

当你的返回数据类型复杂的时候,可以用TypeReference轻松指定返回类型。

输出:

技术分享图片

 

 转载自:https://www.mkyong.com/java/jackson-convert-json-array-string-to-list/

其他参考:https://www.cnblogs.com/dupang/p/5673097.html

jackson将json数组转成List、普通数组。

原文:https://www.cnblogs.com/passedbylove/p/11464629.html

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