int main() {
return 0; // this is a comment
}
int main() {
return 0;
}
It is guaranteed that all characters are English characters. And to simplify the question, we ensure quotation marks( ‘ and “ ) will not appear.
It is guaranteed that the test cases given can be complied by g++.
If you are confused with some situation, you can write you comments on your IDE(maybe codeblocks) to know what you should output.
虽然是道水题，可是自己还是写了好久，可能是我太菜了，写个博客记录一下吧
1 #include <bits/stdc++.h> 2 using namespace std; 3 typedef long long ll; 4 const int maxn=1e5+7; 5 char str[maxn]; 6 int main() 7 { 8 ll x=1; 9 /*x*/x*=x;/*x*/x*=x;/*x*/x*=x;/*x*/x*=x;/*x*/x*=x;/*x*/x*=x;/*x*/x=8*2;/*x*/ 10 /*123/*//*/**/ 11 /*123/*//*/*123*/ 12 /*123/*//*123/*123*/ 13 /*123/*123//*123/*123*/ 14 15 /* 16 int main() { 17 return 0; // this is a comment 18 } 19 */ 20 //样例测试用 21 22 int flag=0; 23 while(gets(str)) 24 { 25 int len=strlen(str); 26 int i=0; 27 while(i<len) 28 { 29 if(flag==0&&i<len-1&&str[i]==‘/‘&&str[i+1]==‘/‘) 30 { 31 str[i]=‘1‘,str[i+1]=‘1‘; 32 flag=1; 33 i+=2; 34 } 35 if(flag==0&&i<len-1&&str[i]==‘/‘&&str[i+1]==‘*‘) 36 { 37 str[i]=‘1‘,str[i+1]=‘1‘; 38 flag=2; 39 i+=2; 40 } 41 if(i<=len-1&&flag==0)putchar(str[i]),++i; 42 if(flag==2&&i<len-1&&str[i]==‘*‘&&str[i+1]==‘/‘) 43 { 44 str[i]=‘1‘,str[i+1]=‘1‘; 45 flag=0; 46 i+=2; 47 } 48 if(flag!=0)++i; 49 } 50 if(flag==1||flag==0) 51 { 52 flag=0; 53 puts(""); 54 } 55 } 56 return 0; 57 }
原文：https://www.cnblogs.com/CharlieWade/p/11474795.html