输入一个字符串,包括数字字母符号,可以为空
如果是合法的数值表达则返回该数字,否则返回0
+2147483647
1a33
2147483647
0
题目链接:
https://www.nowcoder.com/practice/1277c681251b4372bdef344468e4f26e?tpId=13&tqId=11202&rp=3&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking
package com.sunshine.OFFER66_SECOND; import org.junit.Test; public class A49_StrToInt { @Test public void test() { String str = "+2147483647"; String str2 = "-9"; int i = StrToInt(str2); System.out.println(i); } public int StrToInt(String str) { if (null == str || "".equals(str)) { return 0; } int flag = 1; int ans = 0; int index = 10; char[] chars = str.toCharArray(); for (int i = 0; i < chars.length; i++) { if (i == 0 && ‘-‘ == (chars[i])) { flag = -1; } else if (i == 0 && ‘+‘ == chars[i]) { flag = 1; } else if (chars[i] >= 48 && chars[i] <= 57) { ans = ans * index + (chars[i] - 48); } else { return 0; } } return ans * flag; } }
原文:https://www.cnblogs.com/MoonBeautiful/p/11477050.html