图的深度优先遍历c++实现

图的深度优先遍历c++实现

• 深度优先搜索

邻接矩阵的创建

    int i, j, m, a, b;
    cin >> n >> m;
    //初始化二维矩阵
    for (i = 1; i <= n; i++)
        for (j = 1; j <= n; j++)
            if (i == j)e[i][j] = 0;
            else e[i][j] = 0x3f;

    //读入顶点之间的边
    for (i = 1; i <= m; i++)
    {
        cin >> a >> b;
        e[a][b] = 1;
        e[b][a] = 1; //无向图需要将其对应的点的左边也赋值为1
    }

深度优先搜索算法实现

void dfs(int cur)
{
    int i;
    cout << cur << " ";
    sum++;//每访问一个节点sum就++
    if (sum == n)return;//所有的顶点已经访问过直接退出
    for (int i = 1; i <= n; i++)
    {
        //判断当前顶点cur到顶点i是否有边,并判断顶点i是否已经访问过
        if (e[cur][i] == 1 && book[i] == 0)
        {
            book[i] = 1;
            dfs(i);
        }
    }
    return;
}

整体代码

#include <iostream>
#include <cstdio>
using namespace std;
int book[101], sum, n, e[101][101];

void dfs(int cur)
{
    int i;
    cout << cur << " ";
    sum++;//没访问一个节点sum就++
    if (sum == n)return;//所有的顶点已经访问过直接退出
    for (int i = 1; i <= n; i++)
    {
        //判断当前顶点cur到顶点i是否有边,并判断顶点i是否已经访问过
        if (e[cur][i] == 1 && book[i] == 0)
        {
            book[i] = 1;
            dfs(i);
        }
    }
    return;
}
int main()
{
    int i, j, m, a, b;
    cin >> n >> m;
    //初始化二维矩阵
    for (i = 1; i <= n; i++)
        for (j = 1; j <= n; j++)
            if (i == j)e[i][j] = 0;
            else e[i][j] = 0x3f;

    //读入顶点之间的边
    for (i = 1; i <= m; i++)
    {
        cin >> a >> b;
        e[a][b] = 1;
        e[b][a] = 1; //无向图需要将其对应的点的左边也赋值为1
    }

    //从顶点1出发
    book[1] = 1;//标记一号顶点已经被访问
    dfs(1);//从1号顶点开始遍历
    system("pause");
    return 0;
}

图的深度优先遍历c++实现

原文：https://www.cnblogs.com/wlw-x/p/11509384.html