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Oracle数据库按正则切割字符串

时间:2019-09-12 10:33:51      阅读:97      评论:0      收藏:0      [点我收藏+]

1、方法一:

SELECT regexp_substr(161,83,66,81,[0-9]+,1,LEVEL) FROM dual
CONNECT BY  level <= length(161,83,66,81) - length(regexp_replace(161,83,66,81,,,‘‘)) + 1;

另附流程备份如下(注意最后的分号在流程中是否需要):

SELECT ID ,DEPARTMENTID ,LASTNAME  FROM HRMRESOURCE WHERE LOGINID IS NOT NULL AND DEPARTMENTID IN
(SELECT regexp_substr(t.deptid,[0-9]+,1,LEVEL) FROM (SELECT (CASE to_char(DEPARTMENTID) WHEN to_char(161)
THEN 161||,||81||,||66||,||83 ELSE to_char(DEPARTMENTID) END ) deptid FROM HRMRESOURCE WHERE DEPARTMENTID = 161) t
CONNECT BY  level <= length(t.deptid) - length(regexp_replace(t.deptid,,,‘‘)) + 1) AND LASTNAME NOT LIKE %离职%;

 

Oracle数据库按正则切割字符串

原文:https://www.cnblogs.com/suhfj-825/p/11510283.html

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