1 class Solution: 2 def tribonacci(self, n: int) -> int: 3 if n<1: 4 return n 5 if n==2: 6 return 1 7 a=[0,1,1] 8 m=0 9 t=1 10 s=2 11 while s<=n-1: 12 a.append(a[m]+a[t]+a[s]) 13 m,t,s=t,s,s+1 14 return a[-1]
原文:https://www.cnblogs.com/taoyuxin/p/11596372.html