Python 练习二

l1 = [11,22,33]
l2 = [22,33,44]
# a,获取内容相同的元素
# b 获取l1 中有, l2 中没有的元素列表
# c 获取l2 中有, l1 中没有的元素列表
# d 获取l1  和l2 中内容都不同的元素

#a
for i in  l1:
    if i in l2:
        print(i)
#b
for i in l1:
    if i not in l2:
        print(i)
#c
for i in l2:
    if i not in l1:
        print(i)
#d
for i in l1:
    if i not in l2:
        print(i)
for i in l2:
    if i not in l1:
        print(i)

count = 0
for i in range(1,9):
    for v in range(1,9):
        if i!=v:
            count += 1
print(count)

count = 0
ls = [1,2,3,4,5,6,7,8]
for i in range(0,len(ls)):
    for v in range(0,len(ls)):
        if i!=v:
            count += 1
print(count)

Python 练习二

原文：https://www.cnblogs.com/159357zzx/p/11596992.html