You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Example:
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 Explanation: 342 + 465 = 807.
代码：
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode* cc=new ListNode(-1), *cur=cc; int carry=0; while(l1||l2){ int val1 = l1 ? l1->val:0; int val2 = l2 ? l2->val:0; int sum=val1+val2+carry; carry=sum/10; cur->next=new ListNode(sum%10); cur=cur->next; if(l1) l1=l1->next; if(l2) l2=l2->next; } if(carry) cur->next=new ListNode(1); return cc->next; } };
参考：
https://www.cnblogs.com/grandyang/p/4129891.html
【Leetcode】2. Add Two Numbers 两数相加
原文：https://www.cnblogs.com/whisperbb/p/11617733.html