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fastjson将json格式字符串转成list集合

时间:2019-10-04 17:04:40      阅读:461      评论:0      收藏:0      [点我收藏+]
 1.gameListStr = "[{"gameId":"1","gameName":"哈哈"},{"gameId":"2","gameName":"呵呵"}]";
2. List<Game> gameList = JSONObject.parseArray(gameListStr, Game.class);
public class Game {
   public String gameId;
   public String gameName;

   public String getGameId() {
      return gameId;
   }

   public void setGameId(String gameId) {
      this.gameId = gameId;
   }

   public String getGameName() {
      return gameName;
   }

   public void setGameName(String gameName) {
      this.gameName = gameName;
   }
}

 

fastjson将json格式字符串转成list集合

原文:https://www.cnblogs.com/qingmuchuanqi48/p/11622399.html

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