小提醒

a = 0
with open("number.txt", "r", encoding="utf8") as f:
    ret = f.readlines()
    for item in ret:
        print(item, type(item))
        for i in item:
            if i.isdigit():
                a+=1
    print(a)

def func(**kwargs):
    for i in kwargs:  # i是每一个键值对得键

        print(i,kwargs[i])


func(ok=1,yes=2,no=3)

# 解析
print(i)
ok
yes
no


print(kwargs)
{‘ok‘: 1, ‘yes‘: 2, ‘no‘: 3}
{‘ok‘: 1, ‘yes‘: 2, ‘no‘: 3}
{‘ok‘: 1, ‘yes‘: 2, ‘no‘: 3}

所以结果是
ok 1
yes 2
no 3