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ES6解构赋值

时间:2019-10-20 23:10:34      阅读:84      评论:0      收藏:0      [点我收藏+]

ES6结构赋值

  左右两边结构一样,声明和赋值不能分开必须要再同一行的代码里面

  1、数组模型的解构

let arr = [1, 2, 3];
let a = arr[0];
let b = arr[1];
let c = arr[2];
console.log(a, b, c); // 1 ,2 ,3
let [a, b, c] = [1, 2, 3];
console.log(a, b, c); // 1 2 3
// 嵌套
let [a, [[b], c]] = [1, [[2], 3]];
console.log(a, b, c); // 1 2 3
// 忽略
let [a, , b] = [1, 2, 3];
console.log(a, b); // 1  3

 

// 不完全解构
let [a = 1, b] = []; 
console.log(a, b); // a = 1, b = undefined
// 剩余运算符
let {a, b, ...rest} = {a: 10, b: 20, c: 30, d: 40};
// a = 10
// b = 20
// rest = {c: 30, d: 40}

  2、json解构

let {a, b, c} = {a: 1, b: 2, c: 3};
console.log(a, b, c); // 1 2 3

 

let [{a, b}, [n1, n2], num, str] = [{a: 1, b: 2}, [3, 4], 5, ‘6‘];
console.log(a, b, n1, n2, num, str); // 1 2 3 4 5 "6"
let [json, arr, num, str] = [{a: 1, b: 2}, [3, 4], 5, ‘6‘];
console.log(json, arr, num, str); // {a: 1, b: 2} (2) [3, 4] 5 "6"

 

  3、解构,默认值

let {a = 10, b = 5} = {a: 3};
// a = 3; b = 5;
let {a: aa = 10, b: bb = 5} = {a: 3};
// aa = 3; bb = 5;

  当解构模式有匹配结果,且匹配结果是 undefined 时,会触发默认值作为返回结果。

let [a = 3, b = a] = [];     // a = 3, b = 3 a 与 b 匹配结果为 undefined ,触发默认值:a = 3; b = a =3
let [a = 3, b = a] = [1];    // a = 1, b = 1 a 正常解构赋值,匹配结果:a = 1,b 匹配结果 undefined ,触发默认值:b = a =1
let [a = 3, b = a] = [1, 2]; // a = 1, b = 2 a 与 b 正常解构赋值,匹配结果:a = 1,b = 2

  4、注意事项

// 左边为数组,右边为json,两边的结构不一样
let [a, b] = {a: 12, b: 34};
console.log(a, b); // 出错
// 右边类型错误,{12, 34} json写法错误
let {a, b} = {12, 34};
console.log(a, b); // Uncaught SyntaxError: Unexpected token 

 

// 声明和赋值分开
let [a, b];
[a , b] = {12, 34};
console.log(a, b); // Uncaught SyntaxError: Missing initializer in destructuring declaration

 

ES6解构赋值

原文:https://www.cnblogs.com/yangWanSheng/p/11710773.html

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