<span style="font-size:18px;">#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define ROWS 4
#define COLS 4
int nums[ROWS][COLS]={{1000,1000,1000,1000},{900,500,400,100},{90,50,40,10},{9,5,4,1}};
char *roms[ROWS][COLS]={{"m","m","m","m"},{"cm","d","cd","c"},{"xc","l","xl","x"},{"ix","v","iv","i"}};/*二维的数组指针*/
void judge(int num)//判断输入的数字是否在制定范围内
{
if(num<1||num>9999)
{
printf("please input the right number!\n");
exit(0);
}
}
void trans(int num,char roman[])//将阿拉伯数字转化为罗马数字
{
int i,j;
roman[0]='\0';/*这一步是非常必要的，因为strcat函数将会找第一个字符串的'\0'，找到之后将其去掉然后
复制字符串，如果不初始化，第二个字符串的内容没法复制在第一个最后*/
for(i=0;i<ROWS;i++)
{
for(j=0;j<COLS;j++)
{
while(num>=nums[i][j])/*设置为循环*/
{
printf("%s\n",roman);
strcat(roman,roms[i][j]);
num-=nums[i][j];
}
}
}
}
void main(int argc,char *argv[])
{
char roman[25];
int low,high;
if(argc<2)
{
printf("please input number!\n");
exit(0);
}
low=high=atoi(argv[1]);//atoi函数就是将字符串转化为整数
judge(low);
if(argc>2)
{
high=atoi(argv[2]);//本程序最多只能成功接收三个字符串
judge(high);
if(low>high)
{
low=high;
high=atoi(argv[1]);
}
}
else
low=1;
for(;low<=high;low++)
{
trans(low,roman);
printf("%4d=%s\n",low,roman);
}
}</span>本程序在dos命令状态中输入文件路径和两个字符串（将会转化成整型），将会输出两个整数之间的所有阿拉伯数的罗马数字。原文：http://blog.csdn.net/zxx150633/article/details/38730141