#include <stdio.h>
int f(void);
// 全局变量
int gALL = 12;
int main(int argc, char const *argv[])
{
printf("in %s gALL=%d\n", __func__,gALL);
f();
printf("agn in %s gALL=%d\n", __func__,gALL);
return 0;
}
int f(void)
{
printf("in %s gALL=%d\n", __func__,gALL);
gALL += 8;
printf("agn in %s gALL=%d\n", __func__,gALL);
return gALL;
}
// in main gALL=12
// in f gALL=12
// agn in f gALL=20
// agn in main gALL=20
如果函数内部存在与全局变量同名的变量,则全局变量被隐藏
#include <stdio.h>
int f(void);
// 全局变量
int gALL = 12;
int main(int argc, char const *argv[])
{
printf("in %s gALL=%d\n", __func__,gALL);
f();
printf("agn in %s gALL=%d\n", __func__,gALL);
return 0;
}
int f(void)
{
// 这里定义一个名字相同的变量,那么全局的就被隐藏了
int gALL = 1;
printf("in %s gALL=%d\n", __func__,gALL);
gALL += 8;
printf("agn in %s gALL=%d\n", __func__,gALL);
return gALL;
}
// in main gALL=12
// in f gALL=1
// agn in f gALL=9
// agn in main gALL=12
#include <stdio.h>
int f(void);
int main(int argc, char const *argv[])
{
f();
f();
return 0;
}
int f(void)
{
static int all = 1;
printf("in %s all=%d\n", __func__,all);
all += 9;
printf("agn in %s all=%d\n", __func__,all);
return all;
}
// in f all=1
// agn in f all=10
// in f all=10
// agn in f all=19
下面的写法就是很危险的
#include <stdio.h>
int* f(void);
void g(void);
int main(int argc, char const *argv[])
{
int *p = f();
printf("*p = %d\n", *p);
g();
printf("*p = %d\n", *p);
return 0;
}
int* f(void)
{
int i = 12;
// 返回本地变量的地址是危险的
return &i;
}
void g(void)
{
int k = 24;
printf("k = %d\n", k);
}
// *p = 12
// k = 24
// *p = 24
原文:https://www.cnblogs.com/mengd/p/11761904.html