剑指offer旋转数组的最小数字python

# -*- coding:utf-8 -*-
class Solution:
    def minNumberInRotateArray(self, rotateArray):
        if rotateArray is None:
            return None
        temp = rotateArray[0]
        for i in range(len(rotateArray) - 1):
            if rotateArray[i] > rotateArray[i+1]:
                temp = rotateArray[i+1]
                break
        return temp