1 let arr = [ 2 {id: 1, name: ‘aaa‘}, 3 {id: 4, name: ‘ddd‘}, 4 {id: 2, name: ‘bbb‘}, 5 {id: 3, name: ‘ccc‘} 6 ] 7 arr.sort((a, b) => { 8 return (a.id + ‘‘) > (b.id + ‘‘)? 1 : -1; 9 }) 10 console.log(arr) // 得到的即为通过id排序好的
原文：https://www.cnblogs.com/zaijin-yang/p/11818849.html