洛谷 P1981 表达式求值（模拟）

 1 #include<cstdio>
 2 #include<iostream>
 3 
 4 using namespace std;
 5 
 6 char c[100005];
 7 long long a[100005];
 8 
 9 int main(){
10     int cnt = 1;
11     long long sum = 0;
12     cin >> a[cnt];
13     a[cnt] %= 10000;
14     while(cin >> c[cnt]){
15         cin >> a[++cnt];
16         a[cnt] %= 10000;
17     }
18     for(int i = cnt; i >= 1; i--){
19         if(c[i] == ‘*‘){
20             a[i] *= a[i+1];
21             a[i] %= 10000;
22             a[i+1] = 0;
23         }
24     }
25     for(int i = 1; i <= cnt; i++) {sum += a[i]; sum %= 10000;}
26     printf("%lld", sum);
27     return 0;
28 }