PAT乙级1003

19分，有点没懂题目意思，隔段时间再回来看看。

import java.util.Scanner;

public class Main {
    public static void main(String[] args){
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        scanner.nextLine();
        for(int i = 0 ; i < n ; ++i){
            String str = scanner.nextLine();
            char[] ch = str.toCharArray();
            int flagp = 0;
            int flaga = 0;
            int flagt = 0;
            int j;
            for( j = 0 ; j < ch.length; ++j){
                if((ch[j] == ‘P‘ && flagp == 0) || (ch[j] == ‘A‘ && flaga < 3) || (ch[j] == ‘T‘ && flagt == 0 && flagp > 0) || ch[j] == ‘ ‘){
                    if(ch[j] == ‘P‘)
                        flagp ++;
                    if(ch[j] == ‘T‘)
                        flagt++;
                    if(ch[j] == ‘A‘ && flagp > 0 && flagt == 0){
                        flaga ++;
                    }
                }else{
                    System.out.println("NO");
                    break;
                }
            }
            if(j == ch.length ) {
                if (flaga > 0 && flagp == 1 && flagt == 1)
                    System.out.println("YES");
                else
                    System.out.println("NO");
            }
        }
    }
}

PAT乙级1003

原文：https://www.cnblogs.com/lin0/p/11925080.html