1266. Minimum Time Visiting All Points

On a plane there are n points with integer coordinates points[i] = [xi, yi]. Your task is to find the minimum time in seconds to visit all points.

You can move according to the next rules:

• In one second always you can either move vertically, horizontally by one unit or diagonally (it means to move one unit vertically and one unit horizontally in one second).
• You have to visit the points in the same order as they appear in the array.

Example 1:

Input: points = [[1,1],[3,4],[-1,0]]
Output: 7
Explanation: One optimal path is [1,1] -> [2,2] -> [3,3] -> [3,4] -> [2,3] -> [1,2] -> [0,1] -> [-1,0]   
Time from [1,1] to [3,4] = 3 seconds 
Time from [3,4] to [-1,0] = 4 seconds
Total time = 7 seconds

Example 2:

Input: points = [[3,2],[-2,2]]
Output: 5

Constraints:

• points.length == n
• 1 <= n <= 100
• points[i].length == 2
• -1000 <= points[i][0], points[i][1] <= 1000

class Solution {
    public int minTimeToVisitAllPoints(int[][] points) {
        int res = 0;
        for(int i = 0; i < points.length - 1; i++){
            res += Math.max(Math.abs(points[i][0] - points[i + 1][0]), Math.abs(points[i][1] - points[i + 1][1]));
        }
        return res;
    }
}

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1266. Minimum Time Visiting All Points

原文：https://www.cnblogs.com/wentiliangkaihua/p/11939477.html