题目描述:
动态规划:O(N^3)
class Solution: def palindromePartition(self, s: str, k: int) -> int: def cost(i, j): r = 0 while i < j: if s[i] != s[j]: r += 1 i += 1 j -= 1 return r n = len(s) f = [cost(0, i) for i in range(n)] for _ in range(k-1): f = [0 if i==0 else min(f[j] + cost(j+1, i) for j in range(i)) for i in range(n)] return f[n-1]
原文:https://www.cnblogs.com/oldby/p/11973064.html