re模块2

# 元字符+，*遇到？后就会变为贪婪匹配 
print(re.findall(‘abc+?‘,‘abcccccc‘))  #[‘abc‘]
print(re.findall(‘abc*?‘,‘abcccccc‘))  #[‘ab‘]
print(re.findall(‘abc{1,4}‘,‘abcccabc‘)) #[‘abccc‘, ‘abc‘]
print(re.findall(‘abc{1,4}?‘,‘abcccabc‘)) #[‘abcc‘, ‘abc‘]
#---------------------------------------------------------------------
#元字符之字符集［］
print(re.findall("[abc]","sdfgbahjkkk"))
#若是字符集的前后没有字母，就会分别匹配a,b,c [‘b‘, ‘a‘],否在就字符集里选择一个字母和外面的连接使用
print(re.findall("a[a-z]","fwefaefewaasfwe")) #[‘ae‘, ‘aa‘]
print(re.findall("a[.*+]","a.b*c+")) #在字符集里的符号就是普通符号  [‘a.‘]

print(re.findall("[^ab]","fgddab"))  #[‘f‘, ‘g‘, ‘d‘, ‘d‘]
print(re.findall("[1-9]","vsd1fdv2sdvsd23")) #[‘1‘, ‘2‘, ‘2‘, ‘3‘]
print(re.findall("d[1-9]","vsd1fdv2sdvsd23")) #[‘d1‘, ‘d2‘]
print(re.findall("[\d]","af1fsdf2ffsf1")) #[‘1‘, ‘2‘, ‘1‘]
print(re.findall("[1-9]","af1fsdf2ffsf1")) #[‘1‘, ‘2‘, ‘1‘]