Given a binary tree, return all root-to-leaf paths.
Note: A leaf is a node with no children.
Example:
Input: 1 / 2 3 5 Output: ["1->2->5", "1->3"] Explanation: All root-to-leaf paths are: 1->2->5, 1->3
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public List<String> binaryTreePaths(TreeNode root) { List<String> res = new ArrayList<>(); if (root == null) { return res; } helper(root, res, ""); return res; } private void helper(TreeNode root, List<String> res, String str) { if (root == null) { return; } if (root.left == null && root.right == null) { res.add(str + root.val); return; } String newStr = str + root.val + "->"; helper(root.left, res, newStr); helper(root.right, res, newStr); } }
原文:https://www.cnblogs.com/xuanlu/p/12001283.html