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python列表和if语句的简单结合

时间:2019-12-12 18:17:57      阅读:93      评论:0      收藏:0      [点我收藏+]

将列表所有元素打印出来

cars = [toyota, honda, mazda, nissan, mitsubishi, subaru, suzuki, isuzu]
for car in cars:
    new_car = car.title()
    print("Japan automobile brand: %s" % new_car)
print("\nAbove is Japan automobile brand !")

输出

技术分享图片
Japan automobile brand: Toyota
Japan automobile brand: Honda
Japan automobile brand: Mazda
Japan automobile brand: Nissan
Japan automobile brand: Mitsubishi
Japan automobile brand: Subaru
Japan automobile brand: Suzuki
Japan automobile brand: Isuzu

Above is Japan automobile brand !
View Code

对列表元素进行判断

japan_cars = [toyota, honda, mazda, nissan, mitsubishi, subaru, suzuki, isuzu, bmc]
germany_cars = bmc
for car in japan_cars:
    if car != germany_cars:
        print("Japan automobile brand: " + car.title())
    else:
        print("Germany automobile brand: " + germany_cars.title())

输出

技术分享图片
Japan automobile brand: Toyota
Japan automobile brand: Honda
Japan automobile brand: Mazda
Japan automobile brand: Nissan
Japan automobile brand: Mitsubishi
Japan automobile brand: Subaru
Japan automobile brand: Suzuki
Japan automobile brand: Isuzu
Germany automobile brand: Bmc
View Code

 测试列表是否为空

为空

cars = []
if cars:
    print("List has tuples.")
else:
    print("List in null.")

 输出

List in null.

不为空

cars = [toyota]
if cars:
    print("List has tuples.")
else:
    print("List in null.")

输出

List has tuples.

 多个列表间进行处理

查询汽车代理商是否代理了指定品牌的汽车

agency_brands = [toyota, honda, nissan, mitsubishi, subaru, suzuki, isuzu, bmc, audi, vw]
query_brands = [ford, audi, mazda]

for query_brand in query_brands:
    if query_brand in agency_brands:
        print("Automobile brand " + query_brand + " in agency contents.")
    else:
        print("We have no " + query_brand + ".")

 输出

We have no ford.
Automobile brand audi in agency contents.
We have no mazda.

 

 

python列表和if语句的简单结合

原文:https://www.cnblogs.com/ilifeilong/p/12030025.html

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