//有多少不同的值
#include<stdio.h>
int main(){
int N,flag,n,num = 0;
scanf("%d",&N);
int a[N];
for(n = 1;n<=N;n++){
flag = 1;
a[0] = -1;
a[n] = n/2+n/3+n/5;
if(a[n] == a[n-1])
flag = 0;
if(flag == 1){
num++;
}
}
printf("%d",num);
return 0;
}
原文：https://www.cnblogs.com/Hqx-curiosity/p/12050738.html