python面试题&练习题之嵌套循环

1*5=5
2*10=20
3*15=45
...
10*50=500

for i in range(1,11):
    print(str(i)+‘x‘+str((i*5))+‘=‘+str((i*i*5)))

方法二：
for a in range(1,11):
    b=a*5;
    print(a,"*",b,"=",a*b);

money = 10000
for i in range(5):
     sum_money = money + money * 0.003
print(num1)

sum = 0;
for year in range(1900,2019):
    if (year%4==0 and year%100!=0) or (year%400==0):
        sum = sum + 366;
    else:
        sum = sum + 365;

for month in range(1,9):
    if month in [1,3,5,7,8,10,12]:
        sum = sum + 31;
    elif month in [4,6,9,11]:
        sum = sum + 30;
    else:
        if (2019% 4 == 0 and 2019 % 100 != 0) or (2019 % 400 == 0):
            sum = sum + 29;
        else:
            sum = sum + 28;

print(sum-1);

for i in range(1,6):
    print(‘*‘*i)

for i in range(1,11,2):
    print(‘*‘*i)

for j in range(1,11,2):
    for i in range(1,11-j,2):
        print(‘#‘,end=‘‘)
    print(‘*‘*j)
  

s = ‘*‘
for i in range(1,10,2):
    print((s*i).center(9))
for i in reversed(range(1,8,2)):
    print((s*i).center(9))

for i in range(1,10):
    for j in range(1,i+1):
        print(str(j)+‘x‘+str(i)+‘=‘+str(j*i),end=‘ ‘)
    print()

list1 = []
for j in range(1,11):
    num = input(‘请输入10个数字，已输入第{}个数‘.format(j))
    num = int(num)
    list1.append(num)
len_sum = len(list1)
for x in range(len_num-1):
    for y in range(len_num-1-x):
        if list1[y]>list1[y+1]:
            list1[y],list1[y+1]=list1[y+1],list1[y]
print(list1)