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ZigZag Conversion

时间:2014-02-17 16:21:53      阅读:345      评论:0      收藏:0      [点我收藏+]

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

 

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

Ref:http://blog.unieagle.net/2012/11/08/leetcode%E9%A2%98%E7%9B%AE%EF%BC%9Azigzag-conversion/

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public class Solution {
    public String convert(String s, int nRows) {
        if (s == null || s.length() == 0 || nRows <= 1) 
            return s;
        
        StringBuilder ret = new StringBuilder();
        int zigsize = 2*nRows -2;
        for(int i = 0; i<nRows; ++i){
            for(int base = i; ; base += zigsize){
                if(base >= s.length())
                    break;
                ret.append(s.charAt(base));
                if(i>0 && i < nRows-1){
                    int ti = base+zigsize -2*i;
                    if(ti < s.length())
                        ret.append(s.charAt(ti));
                }
            }
        }
        return ret.toString();
        
    }
}
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ZigZag Conversion

原文:http://www.cnblogs.com/RazerLu/p/3552019.html

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