这道题思路很简单，就是在一个loop下找最大的和第二大的数值。记住，python最小的数值是-sys.maxsize-1
class Solution: def dominantIndex(self, nums: List[int]) -> int: if not nums or len(nums) == 1: return 0 largest, sec_largest, idx = -sys.maxsize - 1, -sys.maxsize - 1, 0 for i in range(len(nums)): if nums[i] >= largest: sec_largest = largest largest = nums[i] idx = i if nums[i] > sec_largest and nums[i] < largest: sec_largest = nums[i] if largest >= 2 * sec_largest: return idx return -1
[LeetCode] 747. Largest Number At Least Twice of Others
原文：https://www.cnblogs.com/codingEskimo/p/12154613.html