leetcode 869. Reordered Power of 2

function reorderedPowerOf2(N) {
            var a1 = N.toString().split('')
            a1.sort((a, b) =>
                a.localeCompare(b)
            )

            var s1 = a1.join('')

            for (let i = 0; i < 31; i++) {
                var a2 = String(1 << i).split('')
                a2.sort((a, b) =>
                    a.localeCompare(b)
                )
                if (s1 === a2.join(''))
                    return true;
            }

            return false;
        }

leetcode 869. Reordered Power of 2

原文：https://www.cnblogs.com/rubylouvre/p/12175524.html