1022 Digital Library (30分)

本题题意很好读，看上去也不难写
写完运行才发现输出title只有一个单词...
后来把cin >> t换成了getline(cin, t)
还有一个坑点:
Line #1: the 7-digit ID number;
故输出要用%07d

还有key的读入，也需要记忆

/**/
#include <cstdio>
#include <cstring>
#include <cmath>
#include <cctype>
#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <vector>
#include <string>
#include <stack>
#include <queue>

typedef long long LL;
typedef unsigned long long ULL;
using namespace std;

bool Sqrt(LL n) { return (LL)sqrt(n) * sqrt(n) == n; }
const double PI = acos(-1.0), ESP = 1e-10;
const LL INF = 99999999999999;
const int inf = 999999999;
int N, M;
map<string, set<int> > title, author, key, pub, year;

void Q(map<string, set<int> > & mp, string & str)
{
    if(mp.find(str) != mp.end()) {
        for(auto u : mp[str]) printf("%07d\n", u);
        // for(set<int>::iterator it = mp[str].begin(); it != mp[str].end(); it++)
        //  printf("%07d\n", *it);
    }
    else puts("Not Found");
}

int main()
{
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
    scanf("%d", &N);
    for(int i = 0; i < N; i++) {
        int id; scanf("%d\n", &id);
        string t; getline(cin, t);
        title[t].insert(id);
        getline(cin, t); author[t].insert(id);
        while(cin >> t) {
            key[t].insert(id);
            if(getchar() == '\n') break;
        }
        getline(cin, t); pub[t].insert(id);
        getline(cin, t); year[t].insert(id);
    }
    scanf("%d", &M);
    while(M--) {
        int num;
        string s;
        scanf("%d: ", &num);
        getline(cin, s);
        cout << num << ": " << s << "\n";
        if(num == 1) Q(title, s);
        else if(num == 2) Q(author, s);
        else if(num == 3) Q(key, s);
        else if(num == 4) Q(pub, s);
        else if(num == 5) Q(year, s);
    }   

    return 0;
}
/*
    input:
    output:
    modeling:
    methods:
    complexity:
    summary:
*/

1022 Digital Library (30分)

原文：https://www.cnblogs.com/000what/p/12203135.html