题解:直接模拟
#include <cstdio>
int main(){
puts("n e");puts("- -----------");puts("0 1");
double ans=1.0,f=1.0;
for(int i=1;i<=9;i++){
if(i==1)printf("%d %.0lf\n",i,(ans+=(f/=(double)i)));
else if(i==2)printf("%d %.1lf\n",i,(ans+=(f/=(double)i)));
else printf("%d %.9lf\n",i,(ans+=(f/=(double)i)));
}return 0;
}
原文:http://www.cnblogs.com/forever97/p/3945500.html