7 10 2
0 1
0 10
10 10
10 1
9 1
100 3
100 3
1
3
代码实现
#include<iostream>
#include<algorithm>
using namespace std;
#define x first
#define y second
const int N = 1e5 + 10;
typedef pair<int,int> PII;
PII q[N];
int cnt[N];
bool st[N];
int n,d,k;
int main(){
cin >> n >> d >> k;
for(int i = 0;i < n;i++) cin >> q[i].x >> q[i].y;
sort(q,q+n);
for(int i = 0,j = 0;i < n;i++){
cnt[q[i].y] ++;
while(q[i].x - q[j].x >= d){
cnt[q[j].y] --;
j ++;
}
if(cnt[q[i].y] >= k) st[q[i].y] = true;
}
for(int i = 0;i <= 100000;i++) if(st[i]) cout << i << endl;
return 0;
}
原文:https://www.cnblogs.com/luyuan-chen/p/12257974.html